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McNemar’s Test用于配对的2*2表格，例如如果你要比较两个医生对同一个病人治疗效果。一个病人自控，药物治疗前和治疗后结果比较。

McNemar’s Test用于检验(a+b)/N 和（a+c/N）是否显著？

McNemar’s Test的两个分类变量不是独立的，而是相关的，因为(a+b)/N 和（a+c/N）都包含a

McNemar’s Test This is a matched pair test for 2  *   2 tables. For example,

if you want to see if two doctors obtain comparable results

when checking (the same) patients, you would use this test.

 

 

 

 

 

http://www.doc88.com/p-7337013497692.html

 

 

 

 

 

 

 

 

 python代码测试一致

 

# -*- coding: utf-8 -*-''' QQ:231469242,by Toby '''# Import standard packagesimport numpy as npimport scipy.stats as statsimport pandas as pd# additional packagesfrom statsmodels.sandbox.stats.runs import cochrans_q, mcnemar#药物测试，对疾病是否治愈，要求相同对象群体#obs = np.array([[101, 121],[59, 33]])obs = np.array([[2, 4],[0, 4]])def Mcnemar(obs):    '''McNemars Test should be run in the "exact" version, even though approximate formulas are    typically given in the lecture scripts. Just ignore the statistic that is returned, because    it is different for the two options.        In the following example, a researcher attempts to determine if a drug has an effect on a    particular disease. Counts of individuals are given in the table, with the diagnosis    (disease: present or absent) before treatment given in the rows, and the diagnosis    after treatment in the columns. The test requires the same subjects to be included in    the before-and-after measurements (matched pairs).    '''    (statistic, pVal) = mcnemar(obs)    print('\nMCNEMAR\'S TEST -----------------------------------------------------')    print('p = {0:5.3f}'.format(pVal))    if pVal < 0.05:        print("There was a significant change")      else:       print("There was no significant change")Mcnemar(obs)         '''p = 0.125There was no significant change'''

 

 

 

 

例题2

 

python结果无显著差异

 

 

例题3

 

 

 

 

 

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